You cannot, too.
I've tested. The correct way is: {{=XML(str(BR())*5)}}
On 07/25/2012 04:09 PM, Derek wrote:
Ok, how about {{=(BR()*5).XML()}}
On Wednesday, July 25, 2012 11:53:05 AM UTC-7, viniciusban wrote:
They don't work. Output is escaped.
Try it out.
--
Vinicius Assef
On 07/25/2012 03:40 PM, Anthony wrote:
> Though you can do:
>
> |
> {{=BR().xml()*5}}
> |
>
> or
>
> |
> {{=str(BR())*5}}
> |
>
> Anthony
>
> On Wednesday, July 25, 2012 1:23:37 PM UTC-4, viniciusban wrote:
>
> No, you cannot.
>
> On 07/25/2012 02:18 PM, Lucas R. Martins wrote:
> > You also can use {{=BR()*5}} or {{=ANYTHING()*5}}
> >
> > Em Qua 25 Jul 2012 13:51:38 BRT, Toby Shepard escreveu:
> >> In my own html generating libraries, I normally allow
> >> an integer argument to the <BR> maker, which is a count
> >> of how many tags to put out. So:
> >>
> >> {{=BR(5)}}
> >>
> >> could output <BR><BR><BR><BR><BR>
> >>
> >> This works out since the BR tag can't have any components
> >> anyway.
> >>
> >> Just a thought. I find it useful at times.
> >>
> >> Tobiah
> >>
> >
> >
>
> --
>
>
>
--
--
