Better way is this:
{{=XML("<BR/>"*5)}}
But only because you have a ton less brackets.
On Wednesday, July 25, 2012 12:14:09 PM UTC-7, viniciusban wrote:
>
> You cannot, too.
>
> I've tested. The correct way is: {{=XML(str(BR())*5)}}
>
>
>
>
> On 07/25/2012 04:09 PM, Derek wrote:
> > Ok, how about {{=(BR()*5).XML()}}
> >
> > On Wednesday, July 25, 2012 11:53:05 AM UTC-7, viniciusban wrote:
> >
> > They don't work. Output is escaped.
> >
> > Try it out.
> >
> > --
> > Vinicius Assef
> >
> >
> > On 07/25/2012 03:40 PM, Anthony wrote:
> > > Though you can do:
> > >
> > > |
> > > {{=BR().xml()*5}}
> > > |
> > >
> > > or
> > >
> > > |
> > > {{=str(BR())*5}}
> > > |
> > >
> > > Anthony
> > >
> > > On Wednesday, July 25, 2012 1:23:37 PM UTC-4, viniciusban wrote:
> > >
> > > No, you cannot.
> > >
> > > On 07/25/2012 02:18 PM, Lucas R. Martins wrote:
> > > > You also can use {{=BR()*5}} or {{=ANYTHING()*5}}
> > > >
> > > > Em Qua 25 Jul 2012 13:51:38 BRT, Toby Shepard escreveu:
> > > >> In my own html generating libraries, I normally allow
> > > >> an integer argument to the <BR> maker, which is a count
> > > >> of how many tags to put out. So:
> > > >>
> > > >> {{=BR(5)}}
> > > >>
> > > >> could output <BR><BR><BR><BR><BR>
> > > >>
> > > >> This works out since the BR tag can't have any components
> > > >> anyway.
> > > >>
> > > >> Just a thought. I find it useful at times.
> > > >>
> > > >> Tobiah
> > > >>
> > > >
> > > >
> > >
> > > --
> > >
> > >
> > >
> >
> > --
> >
> >
> >
>
>
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