You’ll need to manually copy Function.prototype.apply to the TestClass
prototype.
Another option is “Function.prototype.apply.call(TestClass, this, arguments)”.
Geoff
> On Oct 2, 2014, at 8:26 AM, Moritz Moeller <mmoel...@mxs.de> wrote:
>
> Hi,
>
> I’ve created a javascript class in native code (i.e. JSClassCreate,
> JSObjectMakeConstructor etc.) and want to subclass this class in javascript.
>
> So pretty much:
>
> JSClassDefinition classDef = kJSClassDefinitionEmpty;
> classDef.className = "TestClass";
> classDef.getProperty = class_getProperty;
> classDef.setProperty = class_setProperty;
> JSClassRef classRef = JSClassCreate(&classDef);
> JSObjectRef constructor = JSObjectMakeConstructor(ctx, gClassRef,
> class_constructor);
> JSObjectSetProperty(ctx, JSContextGetGlobalObject(ctx),
> JsString("TestClass"), constructor, 0, NULL);
>
> class_constructor does:
> return JSObjectMake(ctx, classRef, NULL);
>
> This works, so I can do
> var test = new TestClass();
> test.field = 1;
>
> and both class_constructor and class_setProperty is called.
>
> Now I’m trying to subclass the TestClass:
> function SubClass()
> {
> TestClass.apply(this, arguments);
> }
>
> here it already got the problem that TestClass - being a constructor - does
> not have .bind() or .apply().
>
> Does someone know how to get this working?
>
> Thank you very much,
>
> Mo
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