…Yet another option is to insert Function.prototype into the TestClass 
prototype chain.

Geoff

> On Oct 2, 2014, at 4:37 PM, Geoffrey Garen <gga...@apple.com> wrote:
> 
> You’ll need to manually copy Function.prototype.apply to the TestClass 
> prototype.
> 
> Another option is “Function.prototype.apply.call(TestClass, this, arguments)”.
> 
> Geoff
> 
>> On Oct 2, 2014, at 8:26 AM, Moritz Moeller <mmoel...@mxs.de 
>> <mailto:mmoel...@mxs.de>> wrote:
>> 
>> Hi,
>> 
>> I’ve created a javascript class in native code (i.e. JSClassCreate, 
>> JSObjectMakeConstructor etc.) and want to subclass this class in javascript.
>> 
>> So pretty much:
>> 
>>     JSClassDefinition classDef = kJSClassDefinitionEmpty;
>>     classDef.className = "TestClass";
>>     classDef.getProperty = class_getProperty;
>>     classDef.setProperty = class_setProperty;
>>     JSClassRef classRef = JSClassCreate(&classDef);
>>     JSObjectRef constructor = JSObjectMakeConstructor(ctx, gClassRef, 
>> class_constructor);
>>     JSObjectSetProperty(ctx, JSContextGetGlobalObject(ctx), 
>> JsString("TestClass"), constructor, 0, NULL);
>> 
>> class_constructor does:
>>     return JSObjectMake(ctx, classRef, NULL);
>> 
>> This works, so I can do
>>     var test = new TestClass();
>>     test.field = 1;
>> 
>> and both class_constructor and class_setProperty is called.
>> 
>> Now I’m trying to subclass the TestClass:
>>     function SubClass()
>>     {
>>         TestClass.apply(this, arguments);
>>     }
>> 
>> here it already got the problem that TestClass - being a constructor - does 
>> not have .bind() or .apply().
>> 
>> Does someone know how to get this working?
>> 
>> Thank you very much,
>> 
>> Mo
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