duh!!!

as soon as I read the response I realized my error.

Thanks

Ted


--- On Tue, 1/4/11, Farrukh Ijaz <[email protected]> wrote:

> From: Farrukh Ijaz <[email protected]>
> Subject: Re: a simple Java question
> To: "Theodore Petrosky" <[email protected]>
> Cc: [email protected]
> Date: Tuesday, January 4, 2011, 7:01 AM
> Hi Ted,
> 
> You should use only estimates().
> 
> if(estimates()) {
>     // your code.
> }
> 
> jobIsClosed() || !jobIsClosed() will always return true as
> at one given moment one of them will be true so anding it to
> estimates() doesn't make sense as if estimates() is false
> the evaluation will quit with false due to java precedence
> which is left to right.
> 
> Farrukh
> 
> On 2011-01-04, at 2:51 PM, Theodore Petrosky wrote:
> 
> > 
> > 
> > if (estimates() && jobIsClosed() ||
> !jobIsClosed()) {}
> > 
> > I have these accessors (estimates() 
> jobIsClosed()). Do I need to parenthesize the second part of
> this to be correct:
> > 
> > if (estimates() && (jobIsClosed() ||
> !jobIsClosed())) {}
> > 
> > 
> > the first example is working as I intend, but I
> originally had:
> > 
> > if (estimates() && jobIsClosed() ||
> estimates() && !jobIsClosed()) {}
> > 
> > 
> > I was reading and searching on Java precedence and
> couldn't find anything that specifically answered the
> question. If I leave my code as the first example, will it
> come back to bite me later? or is the second example more
> correct?
> > 
> > Ted
> > 
> > 
> > 
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