Interestingly, there's something called boolean algebra you can use to
reduce an if statement to its simplest form. According to wikipedia,
It was developed by George Boole, the father of boolean logic, back in
the 1840s. I remember it from the early chapters of a free book, "The
Art of Assembly", which I never finished reading.
http://en.wikipedia.org/wiki/Boolean_algebra_(logic)
Ramsey
On Jan 4, 2011, at 8:55 AM, Theodore Petrosky wrote:
duh!!!
as soon as I read the response I realized my error.
Thanks
Ted
--- On Tue, 1/4/11, Farrukh Ijaz
<[email protected]> wrote:
From: Farrukh Ijaz <[email protected]>
Subject: Re: a simple Java question
To: "Theodore Petrosky" <[email protected]>
Cc: [email protected]
Date: Tuesday, January 4, 2011, 7:01 AM
Hi Ted,
You should use only estimates().
if(estimates()) {
// your code.
}
jobIsClosed() || !jobIsClosed() will always return true as
at one given moment one of them will be true so anding it to
estimates() doesn't make sense as if estimates() is false
the evaluation will quit with false due to java precedence
which is left to right.
Farrukh
On 2011-01-04, at 2:51 PM, Theodore Petrosky wrote:
if (estimates() && jobIsClosed() ||
!jobIsClosed()) {}
I have these accessors (estimates()
jobIsClosed()). Do I need to parenthesize the second part of
this to be correct:
if (estimates() && (jobIsClosed() ||
!jobIsClosed())) {}
the first example is working as I intend, but I
originally had:
if (estimates() && jobIsClosed() ||
estimates() && !jobIsClosed()) {}
I was reading and searching on Java precedence and
couldn't find anything that specifically answered the
question. If I leave my code as the first example, will it
come back to bite me later? or is the second example more
correct?
Ted
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