So you mean the JavaScript should store the path to the component in the
hidden field and the form reads this out (if present) looks-up the
component and calls some (interface) method on the component. This would
be at least JavaScript wise the best solution - I don't know how older
browser behave when the name of the input field is changed.
A problem with this aproach is that Form.onFormSubmitted() is final and I
don't realy know how to parse the path back because the component ids can
be any string - AFAIK.
However also with the current aproach which stays with the 'normal' form
and button behaviour, you can bypass the Form.process().
In the following example there is a DropDownChoice with which you can
either reset or submit the form. You wouldn't need a roundtrip for that.
Anyway important is that the default fromprocessing is turned off, so that
JSButton's onSubmit is called directly without involving the
form-component and that you can use the same aproach for any tag or
component in the page for any JS event.
class ChoiceForm extends JSForm {
String choice = "save";
String value = "";
public ChoiceForm(String id) {
super(id);
setModel(new CompoundPropertyModel(this));
add(new RequiredTextField("value"));
final DropDownChoice dChoice = new DropDownChoice("choice",
Arrays
.asList(new String[] { "save", "reset" }));
add(dChoice);
JSSubmit sub = new JSSubmit("jssubmit") {
protected void onSubmit() {
dChoice.updateModel();
if ("reset".equals(choice)) {
value = "";
} else {
process();//call Form's regular processing
}
};
};
sub.setDefaultFormProcessing(false);//!!
add(sub);
//add the JS to the choice onChange
dChoice.add(new AttributeModifier("onChange", true, new
Model(sub
.getTriggerJavaScript())));
}
//setter/getters
}
What I do not know is how to implement a WebMarkupContainer like JSButton
so that it does not need a tag in the page-templat.
Christian
On Mon, 21 Nov 2005 22:55:48 +0100, Johan Compagner <[EMAIL PROTECTED]>
wrote:
that's not what i mean
Should youre SubmitLink do the normal validation of the form? Is it a
normal
submit?
I think so.
But my other example the onChange on a drop down. If that one is
triggered
it is not a normal submit
The form shouldn't do anything, so defaultFormProcessing == false but
where
is that boolean? It is not a button that is called
So i think by default when the hidden input field of the form where the
event that must be called is in is filled
then the form will not validate it self, so it behaves as a
defaultFormProcessing == false button.
If you want to do a real submit then we should make it easy to call
Form.process() or something.
johan
On 11/21/05, Christian Essl <[EMAIL PROTECTED]> wrote:
> Will check youre code out. i hope this week.
>
> The problem now is that now always should the form completely be
> processed
> and other times is should
> for example a Submit Link should i think process the form. But a
onChange
> listener on a DropDownChoice shouldn't
> That last one shouldn't be a real submit with validation. Just a
submit
> to
> keep the current editting values.
Maybe I don't understand you right.
However I think currently you can use a JSButton with
defaultFormProcessing = false. JSButton is a server-only component. It
does not get rendered in html and it is only there to receive onSubmit()
notificatons. It can be triggered with the script gotten from
JSButton.getTriggerJavaScript() ie by the DrowDownChoice-onClick.
Christian
>
> johan
>
>
> On 11/21/05, Christian Essl <[EMAIL PROTECTED]> wrote:
>>
>> > nice!
>>
>> Thanks
>>
>> > what you do in the submit link i want to do in the form itself (so
the
>> > form
>> > generates a hidden input)
>> > Then everything in that form, Links, onChange listenerers will/can
use
>> > that
>> > one to do the form submit but then dispatch the event)
>> >
>> > johan
>>
>> That's much better. Enclosed is the revised code. For demonstration
>> there
>> is also a wicket Button (JSButton) you can use to trigger from
outside
>> the
>> form and which does itself not render anything.
>>
>> A SubmitLink has now to be inside a JSForm:
>>
>> JSForm f = new JSForm("linkForm", new CompoundPropertyModel(mod));
>> f.add(new TextField("value1"));
>> f.add(new SubmitLink("link1") {
>> protected void onSubmit() {
>> System.out.println("Link1 was clicked, value1 is: "
>> + mod.getValue1());
>> };
>> });
>> f.add(new SubmitLink("link2") {
>> protected void onSubmit() {
>> System.out.println("Link2 was clicked, value1 is: "
>> + mod.getValue1());
>> };
>> });
>>
>> Manuel please test this new code.
>>
>> Christian
>>
>>
>>
--
Christian Essl
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