Jim

As I said this is a rule of thumb and mainly for outdoor LOS setups. This is what most 
wisp uses, as do we, for a general idea for
judging distances and in the field it works well.

Sincerely,  Tony Morella 
Demarc Technology Group, A Wireless Solution Provider 
Office: 908-996-7995 Fax: 908-847-0202
http://www.demarctech.com 


-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Jim Thompson
Sent: Wednesday, January 07, 2004 5:47 AM
To: [EMAIL PROTECTED]
Cc: 'Ivan Bojer'; 'BayArea Wireless UserGroup'
Subject: RE: [BAWUG] Antenna db gain and range


This is only (ever) true if your path-loss coefficient is '2.0', which it almost never 
is.  In fact, in "metro-urban" environments,
it can be 4.0, or higher, and indoor office environments typically range between 3.0 
adn 3.5 (but can go higher).

If your path-loss coefficient is 4.0, then your 6dBm of additional ERIP will only get 
you 1.5dB more in range, or about 1.4X the
range of the solution that is down 6dBm in EIRP.

Jim

[EMAIL PROTECTED] writes:
> A simple rule of thumb is every 3dBm doubles your power and every 6dBm doubles your 
> distance.
> 
> Sincerely,  Tony Morella
> Demarc Technology Group, A Wireless Solution Provider
> Office: 908-996-7995 Fax: 908-847-0202 http://www.demarctech.com
> 
> 
> -----Original Message-----
> From: [EMAIL PROTECTED] 
> [mailto:[EMAIL PROTECTED] On Behalf Of Ivan Bojer
> Sent: Monday, January 05, 2004 3:37 PM
> To: BayArea Wireless UserGroup
> Subject: [BAWUG] Antenna db gain and range
> 
> I know this question is very vague, but still I wonder if there is an answer to it.
> 
> Is there a theoretical formula that links antenna dB gain with 
> increase in maximum range of the wireless signal. I understand that in 
> theory RF signal range is infinity, but I can not figure out if there is a 
> correlation between antenna dB gain and signal range at
certain frequency. Following the common logic it is obvious that range will increase 
as antenna has better dB gain, but how much?
> 
> A formula for electric field goes something like: 
> E=9500*power/distance (I might be wrong about this), but this does not take in 
> account the frequency of our signal.
> 
> P.S. I am not concerned with terrain configuration, weather condition, and other 
> factors at this time.
> 
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