No, it would be enough to have the XML dissector register for the given port in the tcp.port table.
Or have the heuristic dissector register for TCP, but that would be expensive. -- lua snipplet that registers XML on tcp port 12345 DissectorTable.get("tcp.port"):add(12345, Dissector.get("xml")); On 8/2/07, Rick Gudmundson <[EMAIL PROTECTED]> wrote: > Suppose I've got a protocol that is simply XML running over TCP. I know that > Wireshark is capable of dissecting XML data from HTTP packets, etc. What's > the shortest/easiest way to dissect a conversation just as XML? Does it > require a new XML dissector? > > Rick > > _______________________________________________ > Wireshark-dev mailing list > Wireshark-dev@wireshark.org > http://www.wireshark.org/mailman/listinfo/wireshark-dev > > -- This information is top security. When you have read it, destroy yourself. -- Marshall McLuhan Propertarianism joined to capitalist vigor destroyed meaningful commercial competition, but when it came to making good software, anarchism won. -- Eben Moglen _______________________________________________ Wireshark-dev mailing list Wireshark-dev@wireshark.org http://www.wireshark.org/mailman/listinfo/wireshark-dev