No, it would be enough to have the XML dissector register for the
given port in the tcp.port table.

Or have the heuristic dissector register for TCP, but that would be expensive.

-- lua snipplet that registers XML on tcp port 12345
DissectorTable.get("tcp.port"):add(12345, Dissector.get("xml"));



On 8/2/07, Rick Gudmundson <[EMAIL PROTECTED]> wrote:
> Suppose I've got a protocol that is simply XML running over TCP. I know that
> Wireshark is capable of dissecting XML data from HTTP packets, etc. What's
> the shortest/easiest way to dissect a conversation just as XML? Does it
> require a new XML dissector?
>
> Rick
>
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> Wireshark-dev@wireshark.org
> http://www.wireshark.org/mailman/listinfo/wireshark-dev
>
>


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anarchism won.
-- Eben Moglen
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