Then you can run a normal ping. Merge the captures, and, assuming that both
journies took the same amount of time, you now know:
- the network latency (although note that ICMP may not be given the same
priority as RTP./RTCP traffic)
- how much you might need to time-shift the second trace before merging to
get them in the same time frame


On Thu, Mar 13, 2008 at 6:52 PM, Fabiana moreno <[EMAIL PROTECTED]> wrote:

> My receiver computer is running under windows and the one transmitting the
> video is running under linux.....How can i do this in this case???
>
>
> On 13/03/2008, Rob MacKenzie <[EMAIL PROTECTED]> wrote:
> >
> >  I looked at re-writing ping once to test time difference…  IF your
> > endpoints are in the same building, consider running a wire between the
> > parallel ports and code something to check the exact time when you flip a
> > switch or something.  Then you would have a trigger time for both.
> >
> >
> >  ------------------------------
> >
> > *From:* [EMAIL PROTECTED] [mailto:
> > [EMAIL PROTECTED] *On Behalf Of *Martin Mathieson
> > *Sent:* March 13, 2008 12:13 PM
> > *To:* Community support list for Wireshark
> > *Subject:* Re: [Wireshark-users] end-to-end delay calculation
> >
> >
> >
> > If you have console / command prompt of some type, most operating
> > systems have a ping command that uses ICMP to test connectivity and routrip
> > delay to a remote host and back.
> > But I don't know what OS or environment is running on your endpoints.
> >
> > On Thu, Mar 13, 2008 at 4:05 PM, Fabiana moreno <[EMAIL PROTECTED]>
> > wrote:
> >
> > how can do the ping? I dont know what this is
> >
> >
> >
> > On 13/03/2008, *Martin Mathieson* <[EMAIL PROTECTED]>
> > wrote:
> >
> > You could of course do a ping.  And see how close to the middle the far
> > side sees something happen...
> >
> >
> >
> > On Thu, Mar 13, 2008 at 2:49 PM, Fabiana moreno <[EMAIL PROTECTED]>
> > wrote:
> >
> > Well i did this...but i dont know if it's ideal...i think it would work
> > though....
> >
> > I synchronized the two computers to a server on the internet before
> > every capture so both have the exact same time.
> >
> > i have my sniffer in the two computers, the one that sends and the ones
> > that receive.
> >
> > I created a function in matlab that calculates the difference between
> > those two times...
> >
> > I am being really carefull when i have a packet lost or things like
> > that....
> >
> > But probably this can work???? ...
> >
> >
> >
> > On 13/03/2008, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> >
> > Hi Fabiana,
> >
> >
> >
> > the only way to do that is if you know the time difference between the
> > machines.
> >
> > It´s not so easy however if you use windows you could try synchronizing
> > both endpoints by using:
> >
> > w32tm /config /manualpeerlist:[IP to synchronize to] /update
> > /syncfromflags:MANUAL
> >
> >
> >
> > and then monitor the time difference with:
> >
> > w32tm /stripchart /computer:[IP to synchronize to]
> >
> >
> >
> > ,you always can have a delay reference by pinging and dividing by 2 the
> > RTT.
> >
> >
> >
> > HTH
> >
> > Juan
> >
> >
> >
> >
> >  ------------------------------
> >
> > *From:* [EMAIL PROTECTED] [mailto:
> > [EMAIL PROTECTED] *On Behalf Of *ext Fabiana moreno
> > *Sent:* Miércoles, 12 de Marzo de 2008 09:38 a.m.
> > *To:* Community support list for Wireshark
> > *Subject:* Re: [Wireshark-users] end-to-end delay calculation
> >
> > so ... it is not reliable if i substract the time i hav in the client
> > minus the time i have in the server to get my end the end delay?
> >
> > On 12/03/2008, *Hansang Bae* <[EMAIL PROTECTED]> wrote:
> >
> > Fabiana moreno wrote:
> > > Hello there,
> > >
> > > I know wireshark is not able to calculate the end-to-end delay of a
> > > packet when streaming. I was just wondering if adjusting the clocks of
> > > my two computers(sender and receiver) to the network time protocol and
> > > having the sniffer at both ends i could calculate the end-to-end-delay
> > > tracing each packet. Does this sound logical?
> > >
> >
> >
> > It is within the limits of ntp.  Unless there is a WAN involved, the
> > packets are flying around at an order of magnitude faster than what ntp
> > can provide (ms resolution)
> >
> > --
> >
> > Thanks,
> > Hansang
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> >
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