Hi Dan,
I tried that but using the arrays below
array1: 1,2,3
array2: 1,2,3,4,5
joining the two will give me
1,1,2,2,3,3,4,5
then running distinct leaves me with
1,2,3,4,5
when what I'm trying to get is 4,5
on 10/14/02 12:28 PM, Dan Stein at [EMAIL PROTECTED] wrote:
> Looks to me like you can join the two and then use <@Distinct>
>
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