What is log?
well, with the help of some people in a math chat room, we came up with this:
months = -log(1+(principle*rate/monthlypayment))/log(1+rate)
hope that helps (:
----- Original Message ----- From: "Web Dude" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Tuesday, February 25, 2003 7:44 AM Subject: Re: Witango-Talk: One for the Math Wizards
I guess not...'years'>*12)">>
>I have a problem I am hoping someone with a better head for math can >help me figure out. > >I have built a mortgage calculator that seems to be relatively >accurate and now would like to do the same with credit card debt. >The mortgage calulator works like so... > ><@ASSIGN gPower <@CALC "(1+<@POSTARG 'rate'>/1200)^(<@POSTARG> >Monthly Payement = <@CALC "(<@POSTARG 'amount'>*<@POSTARG >'rate'>*<@VAR gpower>)/(1200*(<@VAR gpower>-1))" PRECISION="2" >FORMAT="num:3-*,\,,2,.,,,,"> > > >Total Cost Of Loan = <@CALC "(<@POSTARG 'amount'>*<@POSTARG >'rate'>*<@VAR gpower>)/(1200*(<@VAR gpower>-1))*(<@POSTARG >'years'>*12)" PRECISION="2" FORMAT="num:3-*,\,,2,.,,,,"> > >Now I found the formula for credit cards after much searching. > >principle = monthlypayment*(1 - (1+rate)^-months)/rate > >This works great when you know the principle, monthly payment, rate >and the number of months but I am trying a new twist to this. > >Suppose you want the client to give you the amount they owe on the >card, the rate and the amount of the payment they would like to >make. How would you come up with the number of months it would take >to pay off the debt, the total amount of the interest paid during >that time and the total cost of the debt? > >Any takers? > >p.s. my head hurts... >-- >________________________________________________________________________ >TO UNSUBSCRIBE: send a plain text/US ASCII email to [EMAIL PROTECTED] > with unsubscribe witango-talk in the message body
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