I don't understand what you mean when you say this involves recursion.

(a)<-+
|   |
(b)  |
|   |
(c)--+
|
(d)

If C takes the route back to A, the whole thing starts back over, so
you'd end up with infinitely nested lists.  The only way I can think
of getting around that would be if there were an idref attribute to
embed list items, so you could have <li id="a"> at the top, and then
for C you'd have <li link="a">.  That'd be.... fun.


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