Here's information on the "750 Hz tone" received at this QTH. I am listing K8R's frequency as reported on my screen. Please explain. The tone frequency reported matched the left edge of the modulated waveforms on the waterfall when I could see tones.*

July 11 RX 21091.0  830 Hz  successful QSO audio "loud", tones obvious
July 14 RX 14091.0  763 Hz  successful QSO audio "loud", tones obvious
July 23 RX 18095.0 795 Hz no QSO yet* Might be propagation is unfavorable.

SO: what is the frequency tolerance of 750 Hz tone for successful decoding?

*FYI several times on the bands I have copied K8R when there were no visible signals from anyone in the waterfall, and including no visible "750 Hz" tone. To me that means Superfox modulation provides excellent results.

Equipment: Windows 10 Dell laptop, TS590SG rig, various antennas.

--Glenn, AF8C

On 7/23/2024 12:16 PM, Steven Franke via wsjt-devel wrote:
On Jul 23, 2024, at 10:41 AM, Black Michael via wsjt-devel <wsjt-devel@lists.sourceforge.net> wrote:

Was looking at this example SuperFox transmission using Audacity

https://www.dropbox.com/scl/fi/stohwy3veidevmwr4j517/240605_181330.wav?rlkey=85h1c9riskq1mmbqzex9hpov3&dl=1
 
<https://www.dropbox.com/scl/fi/stohwy3veidevmwr4j517/240605_181330.wav?rlkey=85h1c9riskq1mmbqzex9hpov3&dl=1>

It looks like there is amplitude modulation going on which would seem to be undesirable. For example, analyzing this one section there is a 1697Hz signal.  But if the amplitude drops the SNR will drop too limiting the decoding ability.
Is amplitude modulation part of the Q-ary polar code?

The SuperFox audio waveform produced by WSJT-X is a constant-envelope Gaussian frequency shift keyed (GFSK) signal with bandwidth-time product BT=8.  The GFSK waveform includes 24 sync symbols at audio tone frequency 750 Hz and 127 polar code symbols at tone frequencies 750 Hz + n*11.71875 Hz, where n is in the range 1-128.

If the transmitter’s upper-sideband audio-to-RF frequency response is flat over the bandwidth of the SuperFox signal (750 Hz - 2262 Hz audio) then the transmitted signal will also have constant envelope. What you are seeing in the example that you posted is the result of frequency-selective fading, i.e. the propagation channel’s frequency response is not flat over the 1512 Hz bandwidth of the SuperFox signal. Most signals will exhibit this effect so some extent.

Steve K9AN


_______________________________________________
wsjt-devel mailing list
wsjt-devel@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/wsjt-devel

--
This email has been checked for viruses by Avast antivirus software.
www.avast.com


_______________________________________________
wsjt-devel mailing list
wsjt-devel@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/wsjt-devel

Reply via email to