Hi all,
Thanks for any help you can give... this has been bugging me for a while.
I have a table that has 2 rows that are used for column headings. However,
some cells span more than one cell. This results in the incorrect calculation
of the column.
Instead of using a "hard coded" index value, I am using a method that finds the
column by heading text and then uses that as the index to reference the cell.
This way if I add or delete columns my code wont break.
But because the header row is made of 2 rows not 1, and the cells might span
more than 1 cell, the calculation is wrong.
EG:
row1 header: 4 cells - "ID", "Desc", "Cost", "Savings"
row2 header: 4 cells - "", "Album Title", "Artist", "Year", "Format", "", ""
in header row2, "Description" spans several cells: "Album Title", "Artist",
"Year", "Format"
Data row: 7 cells - "ID", "Album Title", "Artist", "Year", "Format", "Cost",
"Savings"
So the data row contains a total of 7 columns. And If i look for "Cost" it
will give me an index of 3, but when I use that index to get my value I get the
"Artist" cell value.
I tried getting column_count() but each row returns 4, so that is not helping.
Here is code for my Find column index. It returns column index or nil if not
found.
def find_table_column(tableName, columnName)
tableName = convertToRegex(tableName)
columnName = convertToRegex(columnName)
count = 0
col = nil
[EMAIL PROTECTED] { |t| t.text =~ /#{tableName}/ }
header_row = t.rows.find { |r| r.text =~ /#{columnName}/ }
if (header_row)
header_row.each { |cell|
count += 1
if ((cell ? cell.text : '') =~ /#{columnName}/i )
col = count
end
}
end
return col
end
EG 2:
In the first example, it could be fixed by just replacing "Desc" with the 4
columns, but that is not available to me. In addition, i have tables that work
the other way, several cells in the 1st row are spanned by 1 cell in the 2nd
row.
So a solution should cover both these cases.
Thanks again for any input.
Qaos!
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