On Sun, Sep 16, 2012 at 11:02 AM, Victor Bombi <[email protected]> wrote:
> Hello,
>
> I am triying to compile wxlua with mingw.
>
> wxWidgets 2.9.4 was compiled with mingw :
>
> mingw32-make.exe -f makefile.gcc SHARED=0 UNICODE=0 BUILD=release
> and
> mingw32-make.exe -f makefile.gcc SHARED=0 UNICODE=1 BUILD=release
>
> compiled test named aui with unicode=0 and unicode=1 without problems
>
> Then Cmake with
>
> "C:\Program Files\CMake 2.8\bin\cmake" -G"MinGW Makefiles"
> -DCMAKE_BUILD_TYPE=Release -DwxWidgets_ROOT_DIR=C:/LUA/wxWidgets-2.9.4
> -DwxWidgets_LIB_DIR=C:/LUA/wxWidgets-2.9.4/lib/gcc_lib
> -DwxWidgets_CONFIGURATION=msw -D wxWidgets_VERSION=2.9.x
> -DBUILD_VERBOSELY=TRUE -DBUILD_SHARED_LIBS=FALSE
> -DCMAKE_C_FLAGS=-shared-libgcc -DCMAKE_CXX_FLAGS=-shared-libgcc ../wxlua
>
> stops in linking
>
> CMakeFiles\wxLuaModule.dir/objects.a(luamodule.cpp.obj):luamodule.cpp:(.text+0x29d):
> undefined reference to `wxFormatString::
> AsWChar()'
> ...
You need to edit C:/LUA/wxWidgets-2.9.4/lib/gcc_lib/msw/wx/setup.h and set
#define wxUSE_UNICODE 0
I see that there are some changes with wxWidgets and they are
transitioning to Unicode only. I'm not sure what needs to be done to
smooth this over. I suppose that wxLua's CMake could #define
wxUSE_UNICODE 0 if I detect that you are not using a Unicode build. I
have to think about the best way to fix this.
> the same Cmake but with
>
> -DwxWidgets_CONFIGURATION=mswu
>
> stops in:
>
> Creating library file: ..\..\lib\libwxlua_bind-wx29mswu-2.8.12.dll.a
> C:\LUA\wxWidgets-2.9.4\lib\gcc_lib\libwxmsw29u_core.a(corelib_gdicmn.o):gdicmn.cpp:(.text+0x0):
> multiple definition of `wxGDI
> Object::GetClassInfo() const'
> ..\..\lib\libwxlua-wx29mswu-2.8.12.dll.a(d018392.o):(.text+0x0): first
> defined here
I just built with 2.9.4 (though from SVN, so it may not be exactly the
same 2.9.4) following the install.html instructions w/o a problem.
Can you post this file that should be in the CMake build dir
X:\blah\wxLua-CMakeBuild\modules\CMakeFiles\wxLuaBindLib.dir\link.txt
Regards,
John
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