Hi Alan,
This should be fairly straightforward to accomplish. You'll need to set up
your templates so that when you are processing <loc> elements, you do not
copy <PDSCov> elements to the output. In your template for <lbLocs>, you
could use an xsl:for-each to loop over the <lbloc>elements, recording the
position() of each in a variable, and using it to fetch the corresponding
<loc> element.
You should be able to find lots of XSLT resources online to help you out
with this.
Kevin Cormier
Software Developer, XSLT Development
IBM Toronto Lab, D1-435
E-mail: [EMAIL PROTECTED]
"Alan Andrade"
<[EMAIL PROTECTED]
urity.com> To
<xalan-j-users@xml.apache.org>
04/23/2007 06:38 cc
PM
Subject
RE: can xalan transform 2 xml using
one xslt?
Here is my problem
XML Input
<root>
<locs>
<loc>
<locno>1</locno>
<bldno>1</bldno>
<PDSCov>
<PDSCLSCode>232323</PDSCLSCode>
</PDSCov>
</loc>
<loc>
<locno>1</locno>
<bldno>2</bldno>
<PDSCov>
<PDSCLSCode>556456232323</PDSCLSCode>
</PDSCov>
</loc>
</locs>
<lbLocs>
<lbloc>
<locno>1</locno>
<bldno>1</bldno>
<Covs>
<Cov>
<CLSCode>2424434232323</CLSCode>
</Cov>
</Covs>
</lbloc>
<lbloc>
<locno>1</locno>
<bldno>2</bldno>
<Covs>
<Cov>
<CLSCode>555555</CLSCode>
</Cov>
</Covs>
</lbloc>
</lbLocs>
</root>
Output XML
<root>
<locs>
<loc>
<locno>1</locno>
<bldno>1</bldno>
</loc>
<loc>
<locno>1</locno>
<bldno>2</bldno>
</loc>
</locs>
<lbLocs>
<lbloc>
<locno>1</locno>
<bldno>1</bldno>
<Covs>
<Cov>
<CLSCode>2424434232323</CLSCode>
</Cov>
<Cov>
<CLSCode>232323</CLSCode>
</Cov>
</Covs>
</lbloc>
<lbloc>
<locno>1</locno>
<bldno>2</bldno>
<Covs>
<Cov>
<CLSCode>555555</CLSCode>
</Cov>
<Cov>
<CLSCode>556456232323</CLSCode>
</Cov>
</Covs>
</lbloc>
</lbLocs>
</root>
I need the nodes from one node moved into another.
How do I do this?
Thanks?
Alan
Alan Andrade | [EMAIL PROTECTED]
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