Am 11.03.2011 09:51, schrieb Gilles Chanteperdrix:
Johann Obermayr wrote:
void task_waiter_do(void *data)
{
rt_printf("task_waiter_do started\n");
while(task_waiter_flag == 0)
; // rt_task_sleep( DELAYMS(1) );
rt_printf("task_waiter_do finished\n");
}
What happens if you uncomment the rt_task_sleep here ?
we have some shared code from another RT OS.
And in this code there are some while(hw_state) ; loops.
Could you please give us some more information:
http://www.xenomai.org/index.php/Request_for_information
Do you have priority coupling enabled?
Yes.
We use xenomai 2.5.5.2 and linux kernel 2.6.32.15. gcc 4.3.3
Here you have some more details.
a kernel module have a watchdog checker for some 'user-tasks'
if a 'user-task' have a while loop, than the kernel module will suspend
the user-task and call also the mayday function.
But on some other errorhandling, we have a high priortity watchdog task
control the 'user'-tasks.
On error the watchdog task suspend all user-tasks. (this work correct)
Than the watchdog-task switch off the user-task watchdog.
Make errorhandling and some other function (dump user-task stack)
Than the watchdog task will delete some user-task.
But if a user-task is in a while loop, the system hangs.
in user mode we have no mayday function.
it's look like, that when watchdog-task call rt_task_delete(user_task) ,
the user_task continue running.
Is this so ?
Thanks
Jimmy
--
Mit freundlichen Grüßen, best regards
Johann Obermayr
Software Entwicklung
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