Hi!
Well, I guess I have to start using Xalan then. I can't always know the depth
of the xPath expression, since the argument to countNodes is variable (i.e.
user input). Getting the nodenames are probably an easy task (just need to
parse the argument string for '/'), but since I don't know the depth I can't
really do this in Xerces then...Or I guess I could do it with a recursive
function. Anyway, it seems easier to start learning Xalan right away. It can't
be that hard. =)
Thanks!
//daniel
Erik Rydgren (2003-07-14 21:47):
>You are right this us usually a job for a XPath engine like Xalan. But
>it is very doable in DOM as well as long as your search is static to
>it's nature and doesn't change. According to your question you'll only
>need a double nested loop to accomplish the task you described.
>Something like this.
>(Watch out for pseudo code)
>
>unsigned int nNumFound = 0;
>DOMElement* poRoot = doc->getDocumentElement();
>if (compareNodeName(poRoot, "root")) {
> DOMElement* poRootChild = poRoot->GetFirstChild();
> while (poRootChild) {
> if (compareNodeName(poRootChild, "level1")) {
> DOMElement* poChildChild = poRootChild->getFirstChild();
> while(poChildChild) {
> if (compareNodeName(poChildChild, "level2"))
> nNumFound++;
>
> poChildChild = poChildChild->getNextSibling();
> }
> }
> poRootChild = poRootChild->getNextSibling();
> }
>}
>
>As I said. This is usually best done in Xalan but if you need a small
>footprint and can't handle the overhead applied by Xalan then do it in
>DOM.
>But Xalan WILL make your application more flexible and easier to
>maintain when requirements change.
>
>Regards
>Erik Rydgren
>Mandarin IT
>Sweden
>
>> -----Original Message-----
>> From: Gr�ndal Daniel [mailto:[EMAIL PROTECTED]
>> Sent: den 14 juli 2003 21:09
>> To: [EMAIL PROTECTED]
>> Subject: Help with xPath and DOM
>>
>> Hi!
>>
>> I am kind of new to this stuff and right now I'm trying to count the
>> number of
>> nodes that fulfils a xPath-expression.
>> What I want to do i simple "countNodes(const std::string &xPath)".
>>
>> I should probably do this with Xalan (or?), but can I do it with
>Xerces?
>>
>> This is what I do (roughly) before I want to cound the nodes (I do it
>for
>> other
>> reasons and that's why I want to continue to use my already created
>> parser):
>>
>> impl =
>>
>DOMImplementationRegistry::getDOMImplementation(XMLString::transcode("LS
>")
>> );
>> parser = ((DOMImplementationLS*)
>> impl)->createDOMBuilder(DOMImplementationLS::MODE_SYNCHRONOUS, 0);
>>
>> // set some features on parserobject...
>>
>> doc = parser->parseURI(const_cast<char*>(xml.c_str()));
>>
>> // use doc to useful stuff
>>
>> This should give me a DOM-tree right in doc?
>> So now I want to do doc.countNodes("/root/level1/level2"); // how many
>> nodes is
>> there that looks like this: <root><level1><level2>?
>>
>> I should not be impossible to do something like that...=)
>>
>> Thanks for any suggestions!
>>
>> //daniel
>>
>>
>>
>>
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