Question #207350 on Yade changed: https://answers.launchpad.net/yade/+question/207350
lingran posted a new comment: Hi Bruno and Christian, Thank you very much for pointing out my mistakes and showing me your methods. To better understand your different ways of calculating coordination number, the number of spheres were set to be 5. Here is the list of interactions recorded by Christian's method(notice that the interactions between two spheres are counted twice). ###------------### interactions:id.1, id.2 6 8 3 6 1 6------sphere(id=6) has 5 interactions--(1+2+3+4+5) 6 7 4 6 ---------- 8 7 7 10 1 7------sphere(id=7) has 5 interactions--(1+2+3+4+5) 4 7 6 7 ---------- 6 8 8 7------sphere(id=8) has 4 interactions--(1+2+3+4) 0 8 5 8 ---------- 9 10 5 9 1 9------sphere(id=9) has 4 interactions--(1+2+3+4) 2 9 ---------- 9 10 7 10------sphere(id=10) has 4 interactions--(1+2+3+4) 0 10 4 10 c_wallsphere:interactions between walls and spheres c_spheresphere:interactions between spheres and spheres n_wall=6:the number of walls n_sphere:the number of spheres Z:coordination number According to Bruno's method: Z=2*(c_wallsphere+c_spheresphere)/(n_wall+n_sphere) =2*(12+5)/11=3.0909 According to Christian's method: Z=[(1+2+3+4+5)*2+(1+2+3+4)*3]/(c_wallsphere+2*c_spheresphere) =60/(12+2*5)=2.7272 Two different results,I am a little confused, which one I should take? Sorry for my silly question. Lingran -- You received this question notification because you are a member of yade-users, which is an answer contact for Yade. _______________________________________________ Mailing list: https://launchpad.net/~yade-users Post to : [email protected] Unsubscribe : https://launchpad.net/~yade-users More help : https://help.launchpad.net/ListHelp
