Hey I am trying to solve an issue I have with a broker that opens a zmq router socket and just relay calls to workers via a socket dealer.
The problem is that I don't know how to prevent a second broker to bind itself to the same ipc. Consider the following scripts where I isolate the issue: The server: http://tarek.pastebin.mozilla.org/1649175 The client: http://tarek.pastebin.mozilla.org/1649176 If I run them they happily interact. Now I can run a second server. It will bind the socket but won't do anything or even error out. If I stop the first server, the client will simply lock, as it seems to have a sticky connection to the first server - and won't communicate with the second server until I restart it. As far as I understand, we can only bind() *once*, which make sense. So my question is - shouldn't the second attempt to bind() the socket raise an error ? maybe this is related to the python binding ? If not, how can I know if there's already a socket bound to the ipc ? Cheers Tarek _______________________________________________ zeromq-dev mailing list [email protected] http://lists.zeromq.org/mailman/listinfo/zeromq-dev
