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On 10/17/2010 9:38 AM, Edward Ned Harvey wrote: > > The default blocksize is 128K. If you are using mirrors, then > each block on disk will be 128K whenever possible. But if you're > using raidzN with a capacity of M disks (M disks useful capacity + > N disks redundancy) then the block size on each individual disk > will be 128K / M. Right? > If I understand things correctly, I think this is why it is recommended that you pick an M that divides into 128K evenly. I believe powers of 2 are recommended. I think increasing the block size to 128K*M would be overkill, but that idea does make me wonder: In cases where M can't be a power of 2, would it make sense to adjust the block size so that M still divides evenly? If M were 4 then the data written to each drive would be 32K. So if you really wanted to M to be 5 drives, is there an advantage to making the block size 160K, or if that's too big, how about 80K? Like wise if you really wanted to M to be 3 drives, would adjusting it BS to 96K make sense? -Kyle -----BEGIN PGP SIGNATURE----- Version: GnuPG v2.0.14 (MingW32) iQEcBAEBAgAGBQJMuzG2AAoJEEADRM+bKN5wokMH/A2W3hjf2yZx0uO4n0UvSbIY aAS2faGjx9R03ile3u1K/Qlg/dAm0zLdMkNoKY8Pcg8TPx3VLCapNvmlySxCldAf rPXC8NC5xzIj75oGqb1VGByUlqerCdVldvBjo5vFKcDM83CcpLLjmO6gJzNe1UoV MwcKsb0oZv3JzmYcvqjW/lNCIjaQzxkm0k0EP+pV1tx+HMPyHp+kaxnzv4v994GO zwz0OfUOsHaIkSJda8t8ekg9qMdvZa63X8A0VGmhnR26lpjHZD/274IPBStapasx IC+T7O0EYazQSO3fftZ6MCd9O6//0tbQX0MLHPDMpyX90EU+ihILuqYn/QjJjhg= =4mvO -----END PGP SIGNATURE-----
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