Both ash and hush segfault when asked to evaluate ${0::0/0~09J}.
The stack for integer values in the arithmetic code was too small:
'09J' results in three integers. The leading zero starts an octal
number but '9' isn't an octal digit so '0', '9' and the variable
'Z' are placed on the stack.
Signed-off-by: Ron Yorston <r...@pobox.com>
---
shell/math.c | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)
diff --git a/shell/math.c b/shell/math.c
index 76d22c9bd..83ef85c0c 100644
--- a/shell/math.c
+++ b/shell/math.c
@@ -588,7 +588,8 @@ evaluate_string(arith_state_t *math_state, const char *expr)
/* The proof that there can be no more than strlen(startbuf)/2+1
* integers in any given correct or incorrect expression
* is left as an exercise to the reader. */
- var_or_num_t *const numstack = alloca((expr_len / 2) *
sizeof(numstack[0]));
+ /* Counterexample: 09J results in three integers. */
+ var_or_num_t *const numstack = alloca((expr_len - 2) *
sizeof(numstack[0]));
var_or_num_t *numstackptr = numstack;
/* Stack of operator tokens */
operator *const stack = alloca(expr_len * sizeof(stack[0]));
--
2.38.1
_______________________________________________
busybox mailing list
busybox@busybox.net
http://lists.busybox.net/mailman/listinfo/busybox
