In our club we estimate twice the komi for sente equal to a handicap stone, except for the first handicap stone one, which is just one time the komi.
Using a komi of 6.5 for sente amounts to: Hand. Value 1 = 6.5 2 = 19.5 3 = 32.5 4 = 45.5 5 = 58.5 6 = 71.5 7 = 84.5 8 = 97.5 9 = 110.5 Using a komi of 6 for sente amounts to: Hand. Value 1 = 6 2 = 18 3 = 30 4 = 42 5 = 54 6 = 66 7 = 78 8 = 90 9 = 102 These estimates are fairly close to yours. Dave ----- Oorspronkelijk bericht ----- Van: alain Baeckeroot <[EMAIL PROTECTED]> Datum: vrijdag, januari 5, 2007 8:17 pm Onderwerp: Re: [computer-go] Re: Interesting problem > Le jeudi 4 janvier 2007 22:37, Don Dailey a écrit : > > I have a question. With perfect play, obviously a 9 stone handicap > > game is dead lost. If 2 perfect players played a game where one > > was given the 9 stones, and they played for maximum territory > (obviously> it doesn't make sense to play for a win) would the > handicapped player > > be able to hold some territory at the end of the game? Could he > > carve out a little piece for himself even against his perfect > > opponents wishes? > > > > 9 handicap is equivalent to 120-150 komi (this is estimated by pro > playerstaking 9 handi and playing at maximum strenght) > > 8 h = 100 komi > 4h = 40 komi > > Alain > _______________________________________________ > computer-go mailing list > computer-go@computer-go.org > http://www.computer-go.org/mailman/listinfo/computer-go/ > _______________________________________________ computer-go mailing list computer-go@computer-go.org http://www.computer-go.org/mailman/listinfo/computer-go/
