I think that would be worse. There are lots of sets of 8 numbers that sum the 
same,
far more than there are sets of 8 with the same minimum element.

Arthur

----- Original Message -----
From: Álvaro Begué <[EMAIL PROTECTED]>
Date: Thursday, December 20, 2007 4:08 pm
Subject: Re: [computer-go] rotate board
To: computer-go <computer-go@computer-go.org>

> On Dec 20, 2007 10:19 AM, Jason House <[EMAIL PROTECTED]> 
> wrote:
> >
> >
> > On Dec 20, 2007 10:15 AM, Arthur Cater <[EMAIL PROTECTED]> wrote:
> >
> > > With 8 hashes per position, the chance of two different boards
> > > producing a different set of hashes but
> > > the same canonical hash is greater than 1/2^64, because there 
> will be
> > > a bias in the choice of canonical
> > > hashes - toward numerically lower numbers, for instance.
> > >
> > > I think.
> >
> >
> > More importantly, how does it differ from 8/2^64 = 1/2^61?
> >
> 
> If you are going to compute all 8 hash keys, you can just add them 
> up at the
> end instead of picking the minimum. Wouldn't that be better?
>
_______________________________________________
computer-go mailing list
computer-go@computer-go.org
http://www.computer-go.org/mailman/listinfo/computer-go/

Reply via email to