Stefano, I'm pretty happy that the compiler survived till _union_ of 97 triple patterns. The original explanation did not mean union, I thought it's a peculiar join. The length of union as big as 97 is far beyond any practical purpose. Clearly no need to increase the limit. Just select two columns and fill in your data structure at client side.
Best Regards, Ivan Mikhailov OpenLink Software http://virtuoso.openlinksw.com On Mon, 2012-06-25 at 16:08 +0100, Stefano Ortona wrote: > Hello Ivan, > > On 22/giu/2012, at 18.02, Ivan Mikhailov wrote: > > > Hello Stefano. > > > > On Fri, 2012-06-22 at 17:41 +0100, Stefano Ortona wrote: > > > > > > > my query is very simple: > > > > > > > > > > " > > > > > select distinct ?0 ?1 ...?x ...?100 > > > > > WHERE > > > > > { > > > > > { <certain-dbpedia-resource> rdf:type ?x.} > > > > > } > > > > > " > > > > > > > Query > > SELECT ?s ?t > > from some graph if it is known > > WHERE > > { ?s a ?t . FILTER ( ?s IN (<resource1>, <resource2>, > > <resource3> ...)) } > > (maybe with ORDER BY by ?s for client's convenience). You can't > > preserve the mapping if you return only dependent part of the > > mapping but not the key. > > Anyway the original query is wrong, esp. if many resources have more > > than one type or if at least one resource has no type at all. > > > > > Maybe I didn't explain myself properly, let's go through an example. > Suppose I have 3 resource uri, <http://dbpedia.org/resource/Spain>, > <http://dbpedia.org/resource/Cambridge>, > <http://dbpedia.org/resource/Batman>. I want to retrieve the rdf:type > for every uri. I don't want just a list of union of all types, i wanna > find every type for every single entity, so i want to able to say: > types of Spain are t11,t12,t13...t1n, types of Cambdrige are > t21,t22,t23..t2n, types of Batman are t31,t32,t33...t3n. > > > Using the query you suggested, the final result will contain in > variable ?t the union of all types, therefore i'm not able to > distinguish types of Spain, Cambridge and Batman. > The solution is to use a different variable for every resource, so i'm > using the following query: > > > select distinct ?x ?y ?z > WHERE > { > {<http://dbpedia.org/resource/Spain> rdf:type ?x.} > UNION > {<http://dbpedia.org/resource/Cambridge> rdf:type ?y.} > UNION > {<http://dbpedia.org/resource/Batman> rdf:type ?z.} > } > > > With this query, x contains all types of Spain, y will contains all > types of Cambridge and z all types of Batman. It works also if a > resource has a multiple types, (variable will contain multiple values) > and if a resource doesn't have any type (variable will be empty). > Problem is, using that query with 97 different resources I got the > line of code limit error, any suggestion about? > > > Stefano > ------------------------------------------------------------------------------ Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ _______________________________________________ Dbpedia-discussion mailing list Dbpedia-discussion@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/dbpedia-discussion
