On Saturday, 10 February 2024 at 15:53:09 UTC, Alexander Zhirov
wrote:
Is it possible to calculate the difference between dates in
years using regular means? Something like that
```
writeln(Date(1999, 3, 1).diffMonths(Date(1999, 1, 1)));
```
At the same time, keep in mind that the month and day matter,
because the difference between the year, taking into account
the month that has not come, will be less.
My abilities are not yet enough to figure it out more elegantly.
Maybe I'm not understanding the question, but why not that result
/ 12?
-Steve
