Re: The difference between the dates in years

[Steven Schveighoffer via Digitalmars-d-learn]

On Saturday, 10 February 2024 at 15:53:09 UTC, Alexander Zhirov 
wrote:
Is it possible to calculate the difference between dates in 
years using regular means? Something like that

```
writeln(Date(1999, 3, 1).diffMonths(Date(1999, 1, 1)));
```

At the same time, keep in mind that the month and day matter, 
because the difference between the year, taking into account 
the month that has not come, will be less.

My abilities are not yet enough to figure it out more elegantly.

OK, so I thought this was already taking into account the day of 
the month.

This is what I came up with:

```d
int diffMonthNew(Date d1, Date d2)
{
    auto diff = d1.diffMonths(d2);
    if(diff > 0)
        return diff + (d1.day < d2.day ? -1 : 0);
    else if(diff < 0)
        return diff + (d1.day > d2.day ? 1 : 0);
    return 0;
}
```

Then if you want the years, it would be `diffMonthNew(d1, d2) / 
12`

-Steve