On Sun, 2009-01-11 at 01:53 -0800, Matt Welch wrote:
> I appreciate it. Thank you.
>
> I tried the examples you said and ran into one problem on the first
> ( happened in the second, but fixed ).
>
> On Jan 11, 3:12 am, Malcolm Tredinnick <malc...@pointy-stick.com>
> wrote:
> > On Sun, 2009-01-11 at 00:11 -0800, juice wrote:
> > > > > I then figured it may run into a loop of saving the same model, so i
> > > > > was going to use signals but ran into the same issue that it would
> > > > > still need to be in the save function.
> >
> > > > Are you talking about the infinite loop problem here? I don't understand
> > > > this paragraph.
> >
> > > Yes sir, after talking with webology, he also pointed out it would end
> > > up in an infinite loop. So i went looking into signals.
> >
> > I think you may have thrown out the baby with the bathwater there. All
> > you should have to do is check if the location you retrieve is the same
> > as the current one and, if so, don't do the update. Like this:
> >
> > def save(self, *args, **kwargs):
> > oa = Article.objects.filter(location=self.location)
> > if oa and oa[0] != self:
> > oa = oa(location=0)
> > oa.save()
> > super(Article, self).save(*args, **kwargs)
> >
>
> This returned 'QuerySet' object is not callable, so i changed
> Article.objects.filter -> Article._default_manager.filter(....), still
> returning the same problem with the update.
Oh. This is because I'm an idiot and wasn't concentrating. The lines
oa = oa(location=0)
oa.save()
are bogus. "oa" is a queryset, not an object. It should be
obj = oa[0]
obj.location = 0
obj.save()
Regards,
Malcolm
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