On 7/07/2017 10:40 am, Russell Standish wrote:
On Thu, Jul 06, 2017 at 10:22:40PM +1000, Bruce Kellett wrote:

No, position and momentum are dual in the sense I defined. The
observables are not compatible -- position and momentum are not
simultaneously observable.
I know what you mean by "dual", although the conventional term is
"complementary".

Yes, I was avoiding that term because it is sometimes controversial. But complementarity is a feature of conjugate variables.


Observing S=X+P does not imply simultaneously observing X and P.

As far as I can see, it does. It is not just something you construct by measuring X then P (or vice versa). X and P are operators in different spaces, related by a Fourier transform. Unless you mean measuring the conjugate variables on different members of an ensemble of identically prepared states?

Prove that I can't observe S, or provide a reference to someone doing
so. It appears rather crucial to your critique.

Again, I do not accept the reversal of the burden of proof. X and P are conjugate variables so they are not simultaneously measurable.

On your last point, this is not crucial to my critique of your theory. Well, not unless you are going to rely on this in your proof of linearity. But as I pointed out a while ago, additivity of operators does not imply that the state is a vector in a linear space.

Bruce

--
You received this message because you are subscribed to the Google Groups 
"Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to everything-list+unsubscr...@googlegroups.com.
To post to this group, send email to everything-list@googlegroups.com.
Visit this group at https://groups.google.com/group/everything-list.
For more options, visit https://groups.google.com/d/optout.

Reply via email to