Hi, I habe a current system, where i have current and 12.2-STABLE jails. Checking with jls, i get this output:
root@fbsd13:~ # jls -h jid name ip4.addr host.hostname vnet osrelease path | column -t jid name ip4.addr host.hostname vnet osrelease path 8 j0 192.168.0.10 j0.local 2 13.0-CURRENT /jails/j0 10 j1 - j1.local 1 13.0-CURRENT /jails/j1 12 j2 - j2.local 1 13.0-CURRENT /jails/j2 the jails are running this versions: root@fbsd13:~ # jexec -l j0 freebsd-version -u 12.2-STABLE root@fbsd13:~ # jexec -l j1 freebsd-version -u 13.0-CURRENT root@fbsd13:~ # jexec -l j2 freebsd-version -u 12.2-STABLE What is "osrelease"? Looking at the name, i would have guessed, it is the version of the freebsd userland, running in the jail. But it does't seem so. j1 and j2 are VNET jails, so it seems the 1 in the vnet column signifies this, j0 is a "standard" jail using the hosts network stack, so the 2 stands for standard? Is ist possible for jls to get the ip address and the userland version of/in the jail? Or is the only way to get this information to jexec ifconfig and freebsd-version? -- Martin _______________________________________________ freebsd-jail@freebsd.org mailing list https://lists.freebsd.org/mailman/listinfo/freebsd-jail To unsubscribe, send any mail to "freebsd-jail-unsubscr...@freebsd.org"
