Hello! I was wondering: is the Haskell default runtime (that which uses only one processor) scheduler able to interrupt a thread which is currently calling to a C function in order to enable another haskell thread to progress? I think it can't, because I have starvation problems when I have a thread which calls inside its loop to a C function which makes a little "sleep".
BTW, what is the portable way to sleep a thread in Haskell ? Control.Concurrent.threadDelay is "GHC only". ----- Yves Parès Live long and prosper -- View this message in context: http://old.nabble.com/Threading-and-FFI-tp27611528p27611528.html Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
