On Tue, Feb 16, 2010 at 09:00:08AM -0800, Yves Parès wrote: > I was wondering: is the Haskell default runtime (that which uses only one > processor) scheduler able to interrupt a thread which is currently calling > to a C function in order to enable another haskell thread to progress? > I think it can't, because I have starvation problems when I have a thread > which calls inside its loop to a C function which makes a little "sleep".
Did you try marking the call as safe? Cheers, -- Felipe. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
