On Wed, Jan 4, 2012 at 7:58 PM, Yves Parès <limestr...@gmail.com> wrote: > f :: forall a. a -> a > f x = x :: forall a. a > > Which is obviously wrong: when you have entered f, x has been instatiated to > a specific type 'a', and then you want it to x to be of any type? That > doesn't make sense.
I did not expect the type variables to be scoped. I expected the type of 'x' to be universally quantified, and thus can be unified with 'forall a. a' with no problem. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
