Hi Hut, In simple terms...
This is a standard Java feature. The compiler knows that one or more calls in your method can throw a particular Exception. You either need to implement a try/catch block around that/those methods, or declare that your method can throw that kind of Exception. -Chris > -----Original Message----- > From: Hut Carspecken [mailto:[EMAIL PROTECTED] > Sent: Monday, June 23, 2003 6:22 PM > To: James Users List > Subject: How To: forward Content of a message > > > Hello Again, > > Just one last question I promise. I want to forward the content > of MimeMessage unchanged. I am having trouble with a compile > error that states a thrown type needs to be declared. > > Is there a quick and easy way of simply forwarding a message content? > > Code: > MimeMessage original_msg = mail.getMessage(); > Object original_content = original_msg.getContent(); > > This is the error that i get: > unreported exception javax.mail.MessagingException; must be > caught or declared to be thrown > --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
