Hello list,
This code has been failing for days and I'm at my wit's end. Maybe someone
on this forum can help.
I've coded a bash script that is supposed to loop through managed Linux
systems. It calls another bash script to get records with 8 fields:
local cmd="/usr/local/sbin/zlsexpirations -s -l $nodeList"
local expList # list of nodes and expiration
days
expList=`$cmd` # run the command
...
So the variable 'expList' has the records. It should then loop through all
the records passing them to the function zSetOneSystem to process one
system at a time. Here's the main loop (the double quotes around expList
are needed to pass a record, not just one token):
local nextLine
while read nextLine; do
zVerbose "calling zSetOneSystem $nextLine"
zSetOneSystem $nextLine
done < <(echo "$expList")
This was my first attempt at the loop:
echo "$expList" |
while read nextLine; do
zVerbose "calling zSetOneSystem $nextLine"
zSetOneSystem $nextLine
done
Both flavors of the loop above have this behavior:
1) If the -n flag (no operation) is passed, the loop runs fine to
completion.
2) If that flag is not passed, the loop runs, processes one system (which
results in files being changed on disk), but then the loop simply stops.
When I trace it, the 'read nextLine' fails. I print out 'expList' after
the loop and all records are still in place. How can a sub-process affect
the parent this way? I've narrowed it down to two resulting bash script
calls nested deeper in zSetOneSystem(). If I comment out those two, the
loop succeeds. If I un-comment either of the two bash scripts, the loop
fails as described. Strange.
Any help will be appreciated.
Thanks.
--
-Mike MacIsaac
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