Steve Graegert wrote:

        char *s;
        int  *i;

        s = (int *)malloc(128 * sizeof(char));
        i = (char *)malloc(128 * sizeof(int));

        s = "malloc is cool!";
        printf("s: %s\n", s);
        printf("s: %d\n", s);

        i = "malloc is cool!";
        printf("i: %s\n", i);
        printf("i: %d\n", i);

This piece of code prints:

        s: malloc is cool!
        s: 4350328
        i: malloc is cool!
        i: 4350328


  The illustration was too simple and good, for me to understand.
  Thanks :)

You see, casting changes the interpretation of bits when they are
read.  The assigment of a particular type to a variable of another
type destroys the original type information (i.e. loss of precision).


  destroys the original type information? Couldn't understand this part.
You are still able to recover the string, regardless of what kind of datatype you store in. The only disadvantage I that, this obscures the logic of the program.

Yes function pointers are legal.  ANSI C99 says:

"J.5.7 Function pointer casts
1 A pointer to an object or to void may be cast to a pointer to a
function, allowing data to be invoked as a function (6.5.4).
2 A pointer to a function may be cast to a pointer to an object or to
void, allowing a
function to be inspected or modified (for example, by a debugger) (6.5.4)."

A function name is just a pointer to the memory location where the
function is found at runtime.  It can be queried, modified and cast to
other types.  It behaves like a variable.  Take a look at the
sigaction structure:

        struct sigaction {
                /* SIG_DFL, SIG_IGN or pointer to function */
void (*sa_handler)(int); ... /* some other fields */
        };

You can define sigaction as follows:

        void handler(int signo) {
                doneflag = 1;
        }

        struct sigaction sa;
        sa.sa_handler = handler;
        ...

Here, sa_handler is registered as a function to be called when the
specified signal occurrs.

Just handle function pointers as simple pointer variables.

  Have still one silly question ---
since you say function pointers are similar to simple pointer variables, and that's why the typecast works, what would the following code mean?

  void handler1 (int a) {

    /* body of handler - 1 */
    printf ("HANDLER - 1 \n");

  }

  void handler2 (int a) {

    /* body of handler - 2 */
    printf ("HANDLER - 2 \n");

  }

  struct sigaction sa;
  sa.sa_handler = (handler2 *) handler1;

  Is this possible? if so, what does it mean?


_z33
--
I love TUX; well... that's an understatement :)

-
To unsubscribe from this list: send the line "unsubscribe linux-c-programming" 
in
the body of a message to [EMAIL PROTECTED]
More majordomo info at  http://vger.kernel.org/majordomo-info.html

Reply via email to