Hi Alex,
On Sat, 30 Mar 2013 22:34:57 +0800, Alex Shi wrote:
> Since the rt task priority is higher than fair tasks, cfs_rq utilization
> is just the left of rt utilization.
>
> When there are some cfs tasks in queue, the potential utilization may
> be yielded, so mulitiplying cfs task number to get max potential
> utilization of cfs. Then the rq utilization is sum of rt util and cfs
> util.
>
> Signed-off-by: Alex Shi <alex....@intel.com>
> ---
> kernel/sched/fair.c | 16 ++++++++++++++++
> 1 file changed, 16 insertions(+)
>
> diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c
> index ae87dab..0feeaee 100644
> --- a/kernel/sched/fair.c
> +++ b/kernel/sched/fair.c
> @@ -3350,6 +3350,22 @@ struct sg_lb_stats {
> unsigned int group_util; /* sum utilization of group */
> };
>
> +static unsigned long scale_rt_util(int cpu);
> +
> +static unsigned int max_rq_util(int cpu)
> +{
> + struct rq *rq = cpu_rq(cpu);
> + unsigned int rt_util = scale_rt_util(cpu);
> + unsigned int cfs_util;
> + unsigned int nr_running;
> +
> + cfs_util = (FULL_UTIL - rt_util) > rq->util ? rq->util
> + : (FULL_UTIL - rt_util);
> + nr_running = rq->nr_running ? rq->nr_running : 1;
This can be cleaned up with proper min/max().
> +
> + return rt_util + cfs_util * nr_running;
Should this nr_running consider tasks in cfs_rq only? Also it seems
there's no upper bound so that it can possibly exceed FULL_UTIL.
Thanks,
Namhyung
> +}
> +
> /*
> * sched_balance_self: balance the current task (running on cpu) in domains
> * that have the 'flag' flag set. In practice, this is SD_BALANCE_FORK and
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