On Wed, 19 Dec 2007, Bill Davidsen wrote:
Justin Piszcz wrote:
On Wed, 19 Dec 2007, Mattias Wadenstein wrote:
On Wed, 19 Dec 2007, Justin Piszcz wrote:
Now to my setup / question:
# fdisk -l /dev/sdc
Disk /dev/sdc: 150.0 GB, 150039945216 bytes
255 heads, 63 sectors/track, 18241 cylinders
Units = cylinders of 16065 * 512 = 8225280 bytes
Disk identifier: 0x5667c24a
Device Boot Start End Blocks Id System
/dev/sdc1 1 18241 146520801 fd Linux raid
If I use 10-disk RAID5 with 1024 KiB stripe, what would be the correct
start and end size if I wanted to make sure the RAID5 was stripe aligned?
Or is there a better way to do this, does parted handle this situation
From that setup it seems simple, scrap the partition table and use the
disk device for raid. This is what we do for all data storage disks (hw
raid) and sw raid members.
Is there any downside to doing that? I remember when I had to take my
machine apart for a BIOS downgrade when I plugged in the sata devices again
I did not plug them back in the same order, everything worked of course but
when I ran LILO it said it was not part of the RAID set, because /dev/sda
had become /dev/sdg and overwrote the MBR on the disk, if I had not used
partitions here, I'd have lost (or more of the drives) due to a bad LILO
As other posts have detailed, putting the partition on a 64k aligned boundary
can address the performance problems. However, a poor choice of chunk size,
cache_buffer size, or just random i/o in small sizes can eat up a lot of the
I don't think you need to give up your partitions to get the benefit of
Bill Davidsen <[EMAIL PROTECTED]>
"Woe unto the statesman who makes war without a reason that will still
be valid when the war is over..." Otto von Bismark
I am doing a benchmark now with:
6 x 400GB (SATA) / 256 KiB stripe with unaligned vs. aligned raid setup.
unligned, just fdisk /dev/sdc, mkpartition, fd raid.
aligned, fdisk, expert, start at 512 as the off-set
Per a Microsoft KB:
Example of alignment calculations in kilobytes for a 256-KB stripe unit
(63 * .5) / 256 = 0.123046875
(64 * .5) / 256 = 0.125
(128 * .5) / 256 = 0.25
(256 * .5) / 256 = 0.5
(512 * .5) / 256 = 1
These examples shows that the partition is not aligned correctly for a
256-KB stripe unit size until the partition is created by using an offset
of 512 sectors (512 bytes per sector).
So I should start at 512 for a 256k chunk size.
I ran bonnie++ three consecutive times and took the average for the
unaligned, rebuilding the RAID5 now and then I will re-execute the test 3
additional times and take the average of that.
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