On 9/20/06, Bill Landry <[EMAIL PROTECTED]> wrote: > Is there a simple way to output to a file all lists with each lists > associated member addresses? I know I can use: > snip > > for each list, but is there a way to do this in one fell swoop, without > having to run through each member list individually? You can do it with some simple shell scripting:
for i in `bin/list_lists -b`; do bin/list_members $i; done -- - Patrick Bogen ------------------------------------------------------ Mailman-Users mailing list Mailman-Users@python.org http://mail.python.org/mailman/listinfo/mailman-users Mailman FAQ: http://www.python.org/cgi-bin/faqw-mm.py Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/ Unsubscribe: http://mail.python.org/mailman/options/mailman-users/archive%40jab.org Security Policy: http://www.python.org/cgi-bin/faqw-mm.py?req=show&file=faq01.027.htp
