Petr Danecek wrote: > Beautiful! The grid lines must be drawn manually? > > On Thu, 2006-12-28 at 13:32 -0700, Jeff Whitaker wrote: > >> Here's a slightly prettier version of my previous example: >> >> from pylab import * >> deltatheta = 2.*pi/100. >> theta = arange(0.,2.*pi+0.5*deltatheta,deltatheta) >> R = arange(0.,pi,deltatheta) >> r,t = meshgrid(R, theta) >> Z = sin(r)*sin(3.*t) >> X = r*cos(t) >> Y = r*sin(t) >> ax = subplot(111) >> cs = ax.contourf(X,Y,Z) >> # make sure aspect ratio preserved >> ax.set_aspect('equal') >> # turn off rectangular frame. >> ax.set_frame_on(False) >> # turn off axis ticks. >> ax.set_xticks([]) >> ax.set_yticks([]) >> # draw a circle around the edge of the plot. >> rmax = max(R) >> ax.plot(rmax*cos(theta),rmax*sin(theta),'k') >> title('Polar contours') >> show() >> >>
Petr: Another option might be to use pcolor, it does work wit polar axes. import pylab # make color-filled plot of polar coordinate data array. # define coordinates. theta = pylab.linspace(0.,2.*pylab.pi,101) R = pylab.linspace(0.,pylab.pi,101) Y,X = pylab.meshgrid(R, theta) # data to plot. Z = pylab.sin(Y)*pylab.sin(4*X) + pylab.exp(-(Y**2/4)) # create subplot. ax = pylab.subplot(111,polar=True) # mesh fill. ax.pcolormesh(X,Y,Z) # make sure aspect ratio preserved ax.set_aspect('equal') pylab.show() -Jeff -- Jeffrey S. Whitaker Phone : (303)497-6313 NOAA/OAR/CDC R/PSD1 FAX : (303)497-6449 325 Broadway Boulder, CO, USA 80305-3328 ------------------------------------------------------------------------- Take Surveys. Earn Cash. Influence the Future of IT Join SourceForge.net's Techsay panel and you'll get the chance to share your opinions on IT & business topics through brief surveys - and earn cash http://www.techsay.com/default.php?page=join.php&p=sourceforge&CID=DEVDEV _______________________________________________ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users