On 10/4/12 4:02 AM, Pierre Haessig wrote:
> Hi Fernando,
>
> Le 04/10/2012 09:16, Fernando Perez a écrit :
>> This would make for an awesome couple of examples for the gallery, the
>> mathematica solutions look really pretty cool:
>>
>> http://mathematica.stackexchange.com/questions/11350/xkcd-style-graphs
> I've never used Mathematica so that it's pretty difficult for me to
> understand the following lines of code which I guess do the main job of
> distorting the image
>
> xkcdDistort[p_] := Module[{r, ix, iy},
> r = ImagePad[Rasterize@p, 10, Padding -> White];
> {ix, iy} =
> Table[RandomImage[{-1, 1}, ImageDimensions@r]~ImageConvolve~
> GaussianMatrix[10], {2}];
> ImagePad[ImageTransformation[r,
> # + 15 {ImageValue[ix, #], ImageValue[iy, #]} &, DataRange ->
> Full], -5]];
>
>
> Is there somebody there that can describe this algorithm with words
> (English or Python ;-)) ?
f@r means f(r)
a~ImageConvolve~b means ImageConvolve(a,b) (~ treats an operator as infix)
Table[..., {2}] means [... for i in range(2)]
#+1& is a lambda function lambda x: x+1
So I think it goes something like:
def xkcdDistort(p):
r = ImagePad(Rasterize(p), 10, Padding='White')
(ix, iy) = [ImageConvolve(RandomImage([-1,1], ImageDimensions(r)),
GaussianMatrix(10))
for i in range(2)]
return ImagePad(ImageTransformation(r,
lambda coord: (coord[0]+15*ImageValue(ix, coord),
coord[1]+15*ImageValue(iy, coord)),
DataRange='Full'),
-5)
Thanks,
Jason
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