On 22.12.19 01:05, Thorsten Glaser wrote:
> Not a definite decision, but consider this:

thanks for the quick reply!

> 
> print -r -- "${x[@]}"
> 
> - vs. -
> 
> a="${x[@]}"
> 
> In the first code, the elements of array x are expanded in list context,
> that is, each element as separate word, unset elements generating no
> words.

yes. that is the expected behaviour for "${x[@]}" expansion (according to my 
reading/understanding, 
of the manpage, anyway).

> 
> In the second code, the elements are expanded in scalar context (because
> they are then assigned to a scalar), that is, the same as in:
> 
> a="${x[*]}"
> 
> First, one string is built from *all* array elements, IFS[0]-separated,
> then it is passed to the assignee.

I can not follow, I'm afraid. the latter behaviour you describe above
is specific for `[*]', no?. i.e.

a="${x[*]}"; print "$a"

produces what you describe above (and the same as `print "${x[*]}"'),
i.e. IFS[0] separated words but

a="${x[@]}"; print "$a"

produces the same as `print "${x[@]}"' i.e. SPACE separated elements 
irrespective of IFS -- as I 
would expect it to be in accord with the difference of `*' and `@' as explained 
in the (m)ksh manpages.

> 
> I think it’s not unusual to consider the argument of a here string
> scalar context.

I have no opinion/knowledge at all in these matters.

> 
> I built here stings in mksh to parallel here documents, where the
> separator is scalar, so this is by coïncidence, but I don’t see anything
> wrong with the mksh behaviour, upon a short two-minute reflection.

that's what I am not sure about. if the POSIX standard or manpage of ksh93 would
allow to determine unambiguously _should_ happen here, than one would have to 
conclude that at least 
one of mksh and ksh93 (or even both!) are wrong, simply because they do behave 
differently.

from this user's perspective, for the initially given example, i.e.

   IFS=$'\n'
   x=(a "b c")

the difference between

   cat <<< ${x[*]}
   cat <<< "${x[*]}"
   cat <<< ${x[@]}
   cat <<< "${x[@]}"

and

   print ${x[*]}
   print "${x[*]}"
   print ${x[@]}
   print "${x[@]}"

is confusing/unexpected (and, as said, there _is_ a difference for ksh93 as 
well, too, but a 
different one than for mksh). the latter (the `prints') do what the manpage 
seems to demand 
regarding the difference between * and @ expansion of the elements and the 
effect of double quoting. 
so I really would expect the here strings to expand in exactly the same way.

so basically I have these questions:

1.
does the standard allow to determine what _should_ happen? if so, is ksh93 
doing it right or mksh? 
or are both wrong and what actually should happen is that the here strings 
behave like in the 
`prints' above?

2.
if the question what is "right" can not be decided by looking at the docs, 
would it not be 
preferable if mksh would mimic ksh (and bash) at this point since consistency 
is preferable (even if 
the behaviour would not be necessarily "better")?

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https://bugs.launchpad.net/bugs/1857195

Title:
  here string behaviour different in mksh and ksh93

Status in mksh:
  New

Bug description:
  consider

  IFS=$'\n'
  x=(a "b c")
  cat <<< ${x[*]}
  cat <<< "${x[*]}"
  cat <<< ${x[@]}
  cat <<< "${x[@]}"

  executing this in mksh (or zsh, incidentally) yields the output

  a
  b c
  a
  b c
  a
  b c
  a
  b c

  (i.e. identical output, always inserting first IFS char between
  elements, for all variants of accessing all elements of the array)
  while ksh93 (or bash, for that matter) yields

  a
  b c
  a
  b c
  a b c
  a b c

  (i.e. `*' behaves different from `@' but double quoting is
  ineffectual).

  I am not sure whether this is a bug (either in ksh93 or mksh) but wanted to 
report this inconsistency and to ask for clarification. what I _would_ have 
expected to start with is, that
  the above "here string" commands would yield the same output as

  print ${x[*]}
  print "${x[*]}"
  print ${x[@]}
  print "${x[@]}"

  which is neither true for ksh93 nor for mksh. is this all good and
  well and I am only overlooking something obvious?

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