On Mon, Sep 13, 2010 at 11:48 AM, Ryan Voots <simcop2...@simcop2387.info> wrote:
> sub foo {
> my $foo = shift;
> $foo = "bar"; }
>
> would not doing a copy for shift like that cause it to act like
>
> sub foo {$_[0] = "bar"} does?
>Well, you know what they say: Try It And See.
