Hi,
In setting out to update our intermediate algebra textbook for the
fall semester (http://msenux.redwoods.edu/IntAlgText/), I've found
that a file that would formerly compile under a previous version of
context will no longer compile.
Preliminaries $ ctxtools --contextversion
CtxTools | context version: 2007.06.06 09:53 (/usr/local/gwTeX/
texmf.local/tex/context/base/context.tex)
CtxTools | context version: 2007.06.06 09:53 (/usr/local/gwTeX/
texmf.local/tex/context/base/cont-new.tex)
Preliminaries $ texmfstart texexec --version
TeXExec | version 6.2.0 - 1997-2006 - PRAGMA ADE/POD
The error message I receive is:
textblocks : reading blocks from NumberSystemsExercises.tub
(./NumberSystemsExercises.tub
textblocks : shortanswer loaded and typeset
textblocks : shortanswer loaded and processed
textblocks : shortanswer loaded and typeset
textblocks : shortanswer loaded and processed
textblocks : shortanswer loaded and typeset
textblocks : shortanswer loaded and processed
textblocks : shortanswer loaded and typeset
textblocks : shortanswer loaded and processed
textblocks : shortanswer loaded and typeset
! Missing number, treated as zero.
<to be read again>
\relax
\dogenfrac ...{\begingroup #4\endgroup #2#3\relax
#5}}
\mathematics #1->\relax \ifmmode #1
\else $#1$\fi
l.216 $ \frac{81}{125}
$
?
The point in the source that seems to cause the difficulty is:
\noindent In \in{Exercises}[ex:secqu.9]-\in[ex:secqu.16],
convert the given decimal to a fraction.
% Exercise #9
\beginquestion
\startquestion[ex:secqu.9]
$0.648$
\stopquestion
\endquestion
\beginlonganswer
\startanswer
There are three decimal places, so
$0.648=\frac{648}{1000}=\frac{81}{125}$.
\stopanswer
\endlonganswer
\beginshortanswer
\startanswer
$\displaystyle \frac{81}{125}$
\stopanswer
\endshortanswer
Shortanswer and longanswer are blocks. Startanswer is an enumeration.
I've tried this in other files and gotten similar errors, which seem
to be tied to the frac command.
Can anyone help?
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