I'm not sure I understand your question: a[[2]] is a matrix.
> a <- list(matrix(1:6,2),matrix(5:10,2))
> is.matrix(a[[2]])
TRUE
x = a[[2]]
> is.matrix(x)
TRUE
> x+2
[,1] [,2] [,3]
[1,] 7 9 11
[2,] 8 10 12
> a[[2]] + 2
[,1] [,2] [,3]
[1,] 7 9 11
[2,] 8 10 12
What else do you need?
Michael Weylandt
On Wed, Aug 24, 2011 at 2:28 PM, Chee Chen <chee.c...@yahoo.com> wrote:
> Dear All,
> As always, I appreciate all your help.
> I would like to know the easiest way to convert each of the homogeneous
> elements of a numeric list into a matrix. Each element of this list is also
> a list such that when displayed, looks like a 2-by-3 matrix , I would like
> to convert each of them into a matrix, without changing the double index of
> each entry.
>
> Suppose:
> a<- vector("list",2)
> > a[[1]]
> [,1] [,2] [,3]
> [1,] 1 2 0
> [2,] 3 4 5
>
> > a[[2]]
> [,1] [,2] [,3]
> [1,] 5 6 9
> [2,] 7 8 10
>
> >is.list(a[[1]])
> True
>
> Target: I would like to convert a[[2]] into a matrix, keeping the double
> index, into
> > mat1
> [,1] [,2] [,3]
> [1,] 5 6 9
> [2,] 7 8 10
>
> The list I have is huge and so is each of its elements, and do not want to
> use unlist because I do not understand it fully.
> Thank you,
> Chee
>
>
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>
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>
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