Sorry for the vagueness of my question, your interpretation, however, was
spot on. Correct me if I am wrong, but my impression is that apply is a more
compact way of a for loop, but that the way R handles them computationally
are the same. In the article I seem to remember, there was a significant
increase in speed with your second approach, presumably because function
calls are avoided in R and the heavy lifting is done in C. I will use your
second approach anyway, but can I expect increased computational efficiency
with it and, if so, is my reasoning in the prior sentence correct?
BTW, it appears as though my own attempt was almost correct, but I did not
transpose the matrix. In genomics, our response variables (genes) are the
rows and the predictor values are the column names. The BioConductor
packages I routinely use are very good at hiding this and I just didn't come
to mind.
Mark
------------------------------------------------------------
Mark W. Kimpel MD ** Neuroinformatics ** Dept. of Psychiatry
Indiana University School of Medicine
15032 Hunter Court, Westfield, IN 46074
(317) 490-5129 Work, & Mobile & VoiceMail
(317) 399-1219 Home
Skype: mkimpel
******************************************************************
On Sun, Oct 5, 2008 at 10:28 AM, Duncan Murdoch <[EMAIL PROTECTED]>wrote:
> On 05/10/2008 10:08 AM, Mark Kimpel wrote:
>
>> I have a large matrix, each row of which needs lm applied. I am certain
>> than
>> I read an article in R-news about this within the last year or two that
>> discussed the application of lm to matrices but I'll be darned if I can
>> find
>> it with Google. Probably using the wrong search terms.
>>
>> Can someone steer me to this article of just tell me if this is possible
>> and, if so, how to do it? My simplistic attempts have failed.
>>
>
> You don't give a lot of detail on what you mean by applying lm to a row of
> a matrix, but I'll assume you have fixed predictor variables, and each row
> is a different response vector. Then you can use apply() like this:
>
> x <- 1:10
> mat <- matrix(rnorm(200), nrow=20, ncol=10)
>
> resultlist <- apply(mat, 1, function(y) lm(y ~ x))
> resultcoeffs <- apply(mat, 1, function(y) lm(y ~ x)$coefficients)
>
>
> "resultlist" will contain a list of 20 different lm() results,
> "resultcoeffs" will be a matrix holding just the coefficients.
>
> lm() also allows the response to be a matrix, where the columns are
> considered different components of a multivariate response. So if you
> transpose your matrix you can do it all in one call:
>
> resultmulti <- lm(t(mat) ~ x)
>
> The coefficients of resultmulti will match resultcoeffs.
>
> Duncan Murdoch
>
> Duncan Murdoch
>
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