Re: e-gold exchange

2005-06-01 Thread Bill Stewart

At 07:22 AM 5/31/2005, Tyler Durden wrote:
OK...what;s the best exchange service for transferring dollars (perhaps 
via paypal or credit cards) into egold?



I haven't found anybody that'll take credit cards or paypal
without either major hurdles or extremely high fees -
there's too much risk of fraud including reneging on credit card charges.

However, I've been very pleased with Goldage.net -
they've got several mechanisms for paying them,
including walking in to one of half a dozen major US banks
and making a deposit to their account,
as well as a few varieties of wire transfer.

They're a transaction-based service rather than an account-based service,
and support a variety of online gold currencies.

I don't use e-gold myself - I get so much spam purporting to be
from them that it's much simpler to discard all of it,
since 99.9% is phishing.  But a certain anonymous person
with whom I might or might not be be familiar was able to
use Goldage's online interface to set up a transaction,
hand some dead presidents to a Bank that's in America,
and a day or two later the transaction cleared and
there was a deposit to an electronic currency company's account,
which could allegedly be used to pay a merchant.
Fees were pretty low, though for relatively small transactions
the minimum fee is the main concern, rather than the
percentages that matter more on larger transactions.



Fwd: Order of an integer

2005-06-01 Thread Sarad AV


--- Cletus Emmanuel [EMAIL PROTECTED] wrote:
Two conjectures (or are they?):

1. The order of an integer 'a' modulo P^m =
P^(m-1)*(Order of a mod P); where P
is an odd prime .

2. If a, m, and n are elements of Z and (a,mn) = 1,
then Order of a mod mn =
QR/(Q,R); where Q = Order of a mod m and R = Order of
a mod n and (Q,R) is the
greatest common divisor function.

For example:

Example 1:Let a =2 and P=7. Then the order of 2 mod 7
= 3 and the order of 2
mod 7^3 = 7^2(3)= 147.

Example 2: The Order of 2 mod 11^2 = 11*(Order of 2
mod 11) = 110

Example 3: The Order of 2 mod (3*7) = (Order of 2 mod
3)*(Order of 2 mod
7)/(U,V) = 2*3/1 = 6; where U = Order of 2 mod 3 and V
= Order of 2 mod 7.

Are any of these two statements known? If so, could
one point me in the
direction? If not can anyone prove or disprove?


---Cletus







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Re: Trojan horse attack involving many major Israeli companies, executives

2005-06-01 Thread Anne Lynn Wheeler

Amir Herzberg wrote:
Nicely put, but I think not quite fair. From friends in financial and 
other companies in the states and otherwise, I hear that Trojans are 
very common there as well. In fact, based on my biased judgement and 
limited exposure, my impression is that security practice is much better 
in Israeli companies - both providers and users of IT - than in 
comparable companies in most countries. For example, in my `hall of 
shame` (link below) you'll find many US and multinational companies 
which don't protect their login pages properly with SSL (PayPal, Chase, 
MS, ...). I've found very few Israeli companies, and of the few I've 
found, two actually acted quickly to fix the problem - which is rare! 
Most ignored my warning, and few sent me coupons :-) [seriously]


Could it be that such problems are more often covered-up in other 
countries? Or maybe that the stronger awareness in Israel also implies 
more attackers? I think both conclusions are likely. I also think that 
this exposure will further increase awareness among Israeli IT managers 
and developers, and hence improve the security of their systems.


there is the story of the (state side) financial institution that was 
outsourcing some of its y2k remediation and failed to perform due 
diligence on the (state side) lowest bidder ... until it was too late 
and they were faced with having to deploy the software anyway.


one of the spoofs of SSL ... was originally it was supposed to be used 
for the whole shopping experience from the URL the enduser entered, thru 
shopping, checkout and payment. webservers found that with SSL they took 
a 80-90% performance hit on their thruput ... so they saved the use of 
SSL until checkout and payment. the SSL countermeasure to MITM-attack is 
that the URL the user entered is checked against the URL in the 
webserver certificate. However, the URL the users were entering weren't 
SSL/HTTPS ... they were just standard stuff ... and so there wasn't any 
countermeasure to MITM-attack.


If the user had gotten to a spoofed MITM site ... they could have done 
all their shopping and then clicked the checkout button ... which might 
provide HTTPS/SSL. however, if it was a spoofed site, it is highly 
probable that the HTTPS URL provided by the (spoofed site) checkout 
button was going to match the URL in any transmitted digital 
certificate. So for all, intents and purposes .. most sites make very 
little use of https/ssl as countermeasure for MITM-attacks ... simply 
encryption as countermeasure for skimming/harvesting (evesdropping).


in general, if the naive user is clicking on something that obfuscates 
the real URL (in some case they don't even have to obfuscate the real 
URL) ... then the crooks can still utilize https/ssl ... making sure 
that they have a valid digital certificate that matches the URL that 
they are providing.


the low-hanging fruit of fraud ROI ... says that the crooks are going to 
go after the easiest target, with the lowest risk, and the biggest 
bang-for-the buck. that has mostly been the data-at-rest transaction 
files. then it is other attacks on either of the end-points. attacking 
generalized internet channels for harvesting/skimming appears to be one 
of the lowest paybacks for the effort. in other domains, there have been 
harvesting/skimming attacks ... but again mostly on end-points ... and 
these are dedicated/concentrated environments where the only traffic ... 
is traffic of interest (any extraneous/uninteresting stuff has already 
been filtered out).