Just van Rossum wrote:
I don't think that in general you want to fold multiple empty lines into
one. This would be my prefered regex:
s = re.sub(r\r\n?, \n, s)
Catches both DOS and old-style Mac line endings. Alternatively, you can
use s.splitlines():
s = \n.join(s.splitlines()) + \n
This also makes sure the string ends with a \n, which may or may not be
a good thing, depending on your application.
s = s.replace(\r, \n[\n in s:])
/F
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