On Wed, Dec 12, 2018 at 9:07 AM yann19 wrote:
> I apologize in advance as this is not much of a Maya question but I am
> trying to convert this 'list' within nested dictionaries into a dictionary
> type.
>
> I had a function where it ingests in a nested dictionary and allows me to
> sort the contents by a specified value eg. name.
> This is a portion of it -
> return {k: {'entries': sorted([v1 for _,v1 in v['entries'].items()], key=
> lambda el: el['name'])} for k,v in dict_data.items()}
>
>
This is a very difficult line to visually parse. At least if the key
function were extracted to its own variable, and if you used
v['entries'].values() then it would be a bit shorter and easier to read.
> However, possibly because I am using [] which returns me a list type.
>
> What I am expecting in the output is something as follow:
> {'my test':
> {
> 'entries': {
> 'name': 'running_slow_v001'
> ...
> },
> ...
> }
> }
>
> but I am getting:
> {'my test':
> {
> 'entries': [{
> 'name': 'running_slow_v001'
> ...
> }],
> ...
> }
> }
>
>
> I tried using `dict()` and tested the placement anywhere within the return
> sentence, it will returns me an error.
> Appreciate in advance for any replies.
>
It sounds like your single line is too complicated if you are just trying
to throw a dict() call into random places in the expression to see if it
works. It might benefit you to unroll this into a proper for loop. But yea,
the reason you are seeing a list is because sorted() takes an interable and
returns a list. From the looks of your example output it appears that each
value of v['entries'] is a dictionary. That means you will have to further
iterate those values to combine them into a single dictionary. One more
complex way to do it in a single line would be to replace the sorted() with:
{k:v for k,v in intertools.chain.from_iterable(d.items() for d in
v['entries'].values())}
But this only further complicates your already complex single line. This is
equivalent to:
entries = {}
for d in v['entries'].values():
entries.update(d)
But as I look at this formatting goal you mentioned, how do you plan to
handle the collisions of the fields in each 'entries' dict value? Is each
one going to have a 'name' field? If so, they are all going to overlay and
the last key wins. The list format would preserve the individual fields of
each entry.
>
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